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*To*: common-lisp at SU-AI*Subject*: More on 0^0*From*: Guy.Steele at CMU-CS-A*Date*: Thu, 02 Dec 1982 06:05:00 -0000

If you take the limit of x^x as x approaches 0 from the northeast (that is, taking on values of the form q+iq where q is real), then, according to my calculations, the limit is e^(-sqrt(2)*pi/8+sqrt(2)*pi/8*i) which is approximately 0.4876+.30275i. Ain't that a kick in he head??? --Guy